Description
Technical Bulletin
Sulphuric acid Equivalent weight = 49
Normality you can decided i.e. you prepare 0.1N
water 1 lit of water
First = Eq.wt x 0.1 N x 1 lit of water
= 49 x 0.1 x 1= 4.9 g
Sulphuric acid you only measure only ml
so you put = gram / (Specific Gravity x Percentage Concentration)
= 49 / (1.83×97)
= 49/177.51
= 2.76 ml of Sulphuric acid you take one litre of water
Label
This range of standardised solutions provides a convienient method for accurate volumetric analysis.
LABEL PROPERTY
Density: >1.0
Soluble in water
Sp. gr.: >1.0
21mPas at 25°C
